Re: [eigen] Vector's -= operator does not seem to work |
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Hello,this is not working, because you are trying to subtract two elements that are different in nature: a vector and a scalar. From a mathematical point of view, it doesn't make sense.By doing v -=2 I assume you are trying to subtract 2 from every component of v. Some software like matlab offer a *shorcut* in the form v - 2, but Eigen doesn't (at least not directly).There are at least two ways to achieve what you want:* v -= Vector3d::Constant(2), that is you express in a proper mathematical way what you want* going into array world as Janos suggested: v.array() -= 2;Note that v *= 2 works because it is mathematically valid to multiply a vector or matrix by a scalar..Best regards,Adrien EscandeOn Wed, Mar 18, 2020 at 10:04 AM Everton Rufino Constantino1 <everton.constantino@xxxxxxx> wrote:Looking at VectorwiseOp.h there is an -= operator implemented...What kind of error are you seeing exactly?Everton ConstantinoSoftware DeveloperApplication Libraries Optimisation
Linux Technology Center, IBM Systems
e-mail: everton.constantino@xxxxxxx----- Original message -----
From: Janos Meny <janos.meny@xxxxxxxxxxxxxx>
To: eigen@xxxxxxxxxxxxxxxxxxx
Cc:
Subject: [EXTERNAL] Re: [eigen] Vector's -= operator does not seem to work
Date: Tue, Mar 17, 2020 21:56
How about using v.array() -= 2; ?On Wed 18. Mar 2020 at 01:53, Hung Dang <hungptit@xxxxxxxxx> wrote:Hi,
I try some Eigen examples (see below) and the -= operator is not
supported. Is there any way to make it work without creating a constant
vector?
Thank a lot,
Hung
Matrix2d a;
a << 1, 2, 3, 4;
Vector3d v(1, 2, 3);
std::cout << "a * 2.5 =\n" << a * 2.5 << std::endl;
std::cout << "0.1 * v =\n" << 0.1 * v << std::endl;
std::cout << "Doing v *= 2;" << std::endl;
v *= 2;
std::cout << "Now v =\n" << v << std::endl;
// Does not work
// v -= 2;
// std::cout << "Now v =\n" << v << std::endl;
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