| Re: [eigen] (vec1*vec2.transpose())*vec3 on 2.0.5/6 |
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- To: eigen@xxxxxxxxxxxxxxxxxxx
- Subject: Re: [eigen] (vec1*vec2.transpose())*vec3 on 2.0.5/6
- From: Márton Danóczy <marton78@xxxxxxxxx>
- Date: Wed, 30 Sep 2009 16:21:50 +0200
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2009/9/30 Rhys Ulerich <rhys.ulerich@xxxxxxxxx>:
> When you're investigating, would you please also check that it behaves
> correctly for
> (vec1*vec1.transpose())*vec2
Just out of curiosity: why would anyone need to compute this kind of
product? The scalar product in vec1*(vec1.dot(vec2)) would be much
faster than forming the rank-1 matrix. Or does Eigen automatically
compute products the fastest way, no matter how bracketing is done?
Marton