|Re: [eigen] Why does Eigen::Quaterniond::angularDistance() method return the absolute angle?|
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Ok, I can see your point regarding angular distance. The issue I'm facing happens for really large angles in my application I have following 2 quaternions:
a = q0.angularDistance(q1) returns 0.30801826469545818 ( ~17.6 deg )
q = q0.conjugate() * q1;
b = 2 * std::atan2( q.vec().norm(), std::fabs(q.w()) ) returns 5.9751670424841281 (342.4 deg)
For my understanding if you wanted to ensure (-pi,pi] the angle should be -17.6 deg
Maybe the atan2 when used with proper quaternions can never return negative values? So the times 2 is used to ensure [0,pi) ?
I did not find the derivation of this formula and even if probably I wouldn't understand it. But at least also here it is written without the absolute value:
From: Gael Guennebaud <gael.guennebaud@xxxxxxxxx>
Sent: Wednesday, August 8, 2018 10:13 AM
Subject: Re: [eigen] Why does Eigen::Quaterniond::angularDistance() method return the absolute angle?
One reasons is that a distance is expected to be symmetric and positive. Another one is that the "sign" is relative to the axis of rotation, so returning a "signed" angular distance alone does not seem to make much sense. Perhaps you want:
and if you really don't care about the axis defining the sign:
double a = AngleAxisd(q1*q2.conjugate()).angle();
On Tue, Aug 7, 2018 at 4:59 PM Dluhosch, Michael <michael.dluhosch@xxxxxxxxxx> wrote:
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