|Re: [eigen] min(Arr1,Arr2) is it supposed to work?|
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On 04/04/11 17:07, Helmut Jarausch wrote:
I've always wondered why the functions should live in the std
Isn't it possible to define a template for min in the namespace Eigen
requiring the user to use Eigen::min (or a using instruction)?
Users should do the following:
- pull std::min in current scope using 'usign std::min'
- call min unqualified
By doing so if their generic type are in Eigen namespace, Eigen::min
will be used by ADL, if not regular one will be.
it is always a godo idea to rely on ADL in these cases. So if Eigen
provides min in namespace Eigen for types living in namespace Eigen,
nothing is required.