Re: [eigen] solve API |

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*To*: eigen@xxxxxxxxxxxxxxxxxxx*Subject*: Re: [eigen] solve API*From*: FMDSPAM <fmdspam@xxxxxxxxx>*Date*: Mon, 28 Jun 2010 17:15:26 +0200

Just my 2 cent: I know, that expression do not have to be evaluated but nevertheless

What about x = b * A.adjoint().lu().invertor() (like benoit's solver()) But cleaner for me to read is, what Manoj suggesting:

x = solve(A,b); // left x = solve(b,A); // right x = solve(b, A.triangularView<Lower>()); // Gael's example

It's OK to read and understand w/o scarring about "inverse()" too. --Frank

**Follow-Ups**:**Re: [eigen] solve API***From:*Manoj Rajagopalan

**Re: [eigen] solve API***From:*Gael Guennebaud

**References**:**[eigen] solve API***From:*Gael Guennebaud

**Re: [eigen] solve API***From:*Manoj Rajagopalan

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