Re: [eigen] solve API

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 Just my 2 cent:

I know, that expression do not have to be evaluated but nevertheless
I would try to avoid the word "inverse()", because of lession #1: "Never use matrix inversion".

What about

x = b * A.adjoint().lu().invertor()	(like benoit's solver())

But cleaner for me to read is, what Manoj suggesting:
     x = solve(A,b); // left
     x = solve(b,A); // right
     x = solve(b, A.triangularView<Lower>()); // Gael's example
It's OK to read and understand w/o scarring about "inverse()" too.


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